4(d+3)^2+3(d+3)=1

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Solution for 4(d+3)^2+3(d+3)=1 equation: 



4(d+3)^2+3(d+3)=1

We move all terms to the left:

4(d+3)^2+3(d+3)-(1)=0

We multiply parentheses

4(d+3)^2+3d+9-1=0

We add all the numbers together, and all the variables

3d+4(d+3)^2+8=0

We move all terms containing d to the left, all other terms to the right

3d+4(d+3)^2=-8

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